Respuesta :
What number will make y^2 + 2y + __ a perfect square?
Take coefficient of y, divide by 2, then square it = (2/2)^2 = 1
So add 1 to both sides, since y^2 + 2y + 1 = (y + 1)^2
y^2 + 2y + 1 = 49
For this case we have the following equation:
[tex]y ^ 2 + 2y = 48[/tex]
By completing squares we have:
Step 1:
Add [tex](\frac {b} {2}) ^ 2[/tex] on both sides:
[tex]y ^ 2 + 2y + 1 = 48 + 1[/tex]
Step 2:
We rewrite the equation:
[tex](y + 1) ^ 2 = 49[/tex]
Step 3:
We solve the equation:
[tex]y = \pm \sqrt {49} -1\\y = \pm7-1[/tex]
Solutions:
[tex]y = 6\\y = -8[/tex]
Answer:
the next line would be:
[tex]y ^ 2 + 2y + 1 = 48 + 1[/tex]