Respuesta :
y = a(1-b)^x
y= final amount
a=original amount
x=time
b= percent change(it would be + if it said increasing) note:change to decimal form.
y=5500 x(1-6%)^(2018-2007)
y= 5500(.94^11)
y= final amount
a=original amount
x=time
b= percent change(it would be + if it said increasing) note:change to decimal form.
y=5500 x(1-6%)^(2018-2007)
y= 5500(.94^11)
Answer:
a. Since, the exponential decay formula is,
[tex]y=a(1-r)^x[/tex]
Where, a is the initial value,
r is the decay rate per period,
x is the number of periods,
Suppose, the population is estimated from the year 2007,
Given,
The population in 2007 is, a = 5500,
Annual rate of decay, r = 6% = 0.06,
Hence, the population after x years,
[tex]y=5500(1-0.06)^x[/tex]
[tex]\implies y=5500(0.94)^x[/tex]
Which is the required equation.
b. for 2018, x = 11 ( number of years since 2007 ),
Thus, the population in 2018 would be,
[tex]y=5500(0.94)^{11}[/tex]
[tex]=2784.64013987[/tex]
[tex]\approx 2785[/tex]
c. The graph of [tex]y=5500(0.94)^{x}[/tex] shown below,
Having no vertical asymptote,
And, horizontal asymptote is y=0
Domain = All possible value of x = { x | x ≥ 0 },
Range = All possible value of y = { y | 0 ≤ y ≤ 5500 }
