A sample of hexane (C6H14) has a mass of 0.580 g. The sample is burned in a bomb calorimeter that has a mass of 1.900 kg and a specific heat of 3.21 J/giK. What amount of heat is produced during the combustion of hexane if the temperature of the calorimeter increases by 4.542 K?
We first calculate the heat released: Specific heat = 3.21 kJ/kgK Heat released = heat absorbed by calorimeter Heat absorbed = mcΔT = 1.9 x 3.21 x 4.542 = 27.7 kJ
Now, we calculate the moles of hexane present: Moles = mass / Mr moles = 0.58 / (12 x 6 + 14) = 0.0067
