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The function below shows the number of car owners f(t), in thousands, in a city in different years t:

f(t) = 1.1t2 - 2.5t + 1.5

The average rate of change of f(t) from t = 3 to t = 5 is ______ thousand owners per year.

Respuesta :

nobillionaireNobley
Average rate of change from a to b = (f(b) - f(a))/(b - a) = {[1.1(5)^2 - 2.5(5) + 1.5] - [1.1(3)^2 - 2.5(3) + 1.5]} / (5 - 3) = (16.5 - 3.9) / 2 = 12.6 / 2 = 6.3

Therefore, the average rate of change of f(t) from t = 3 to t = 5 is 6.3 thousand owners per year.
TaeKwonDoIsDead

Answer:

6.3


Step-by-step explanation:


  • The number of car owners f(t) in year 5 is found by plugging in 5 into t of the equation:

[tex]f(5)=1.1(5)^{2}-2.5(5)+1.5=16.5[/tex]


  • The number of car owners f(t) in year 3 is found by plugging in 3 into t of the equation:

[tex]f(3)=1.1(3)^{2}-2.5(3)+1.5=3.9[/tex]


So there is a change of  [tex]16.5-3.9=12.6[/tex] in the 2 years. So to get per year, we divide 12.6 by 2, to get:

[tex]\frac{12.6}{2}=6.3[/tex]


Hence, "The average rate of change of f(t) from t = 3 to t = 5 is 6.3 thousand owners per year."

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