At a hospital, 56 percent of the babies born are boys. of the baby girls born, 12 percent are premature. what is the probability of a premature baby girl being born at this hospital? round to the nearest percent. 5% 7% 21% 27%

If the likelihood of boys being born is 56%, then the complement of that is the likelihood of girls being born which is 100% - 56% = 44%.
Since we are given that of the baby girls born, 12% are premature, the probability of a premature baby girl being born is:
(0.44)(0.12) = 0.0528 or 5.28%
The closest answer is the FIRST OPTION (5%).

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facundo3141592 facundo3141592 · Answer 2 · 2022-05-18T11:01:49+02:00

The percentage that represents the probability is 5%, so the correct option is the first one.

How to find the probability?

We know that 56% of the babies are boys, then the other 44% are girls.

We also know that 12% of the babies are premature, then the percentage of babies that are girl and premature is given by the product between the two percentages in decimal form:

0.12*0.44 = 0.0528

To get it in percentage form, we get:

100%*0.0528 = 5%

So the correct option is the first one.

If you want to learn more about percentages:

https://brainly.com/question/843074

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