When the ball of mass 0.80kg hits a bowling pin of 0.12 kg, the velocity of the ball after it hits the pin = 12.1 m/s
The mass of the ball, [tex]m_1=0.80 kg[/tex]
The initial speed of the ball, [tex]u_1=13 m/s[/tex]
The mass of the bowling pin, [tex]m_2=0.12kg[/tex]
The initial speed of the bowling pin, [tex]u_2=0m/s[/tex]
The final speed of the bowling pin, [tex]v_2= 6m/s[/tex]
The final speed of the ball after collision, [tex]v_1 = ?[/tex]
According to the law of momentum conservation
[tex]m_1u_1+m_2u_2=m_1v_1+m_2v_2\\\\0.80(13)+0.12(0)=0.80v_1+0.12(6)\\\\10.4+0=0.8v_1+0.72\\\\0.8v_1=10.4-0.72\\\\0.8v_1=9.68\\\\v_1=\frac{9.68}{0.8} \\\\v_1=12.1m/s[/tex]
The velocity of the ball after it hits the pin = 12.1 m/s
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