The sample will also be normally distributed, with same mean as the population, so µ = 70.5, but the standard deviation would be divided by the square root of the sample size, so σ = 2.6/√5 ≈ 1.16.
N(70.5, 1.16)
The sample will also be normally distributed, with the same mean as the population(µ = 70.5) and the standard deviation of 1.16 inches.
A normal distribution is a probability distribution that is used to represent events with a default behaviour and accumulated potential departures from it.
As it is given that the heights of male seniors in high school closely follow a normal distribution N(µ,σ) = N(70.5,2.6), where the units are inches.
Therefore, the mean will be the same (µ = 70.5), but the standard deviation for the sample size of the heights of five male seniors, can be written as,
[tex]s=\dfrac{\sigma}{\sqrt n} = \dfrac{2.6}{\sqrt5} = 1.16[/tex]
Hence, The sample will also be normally distributed, with the same mean as the population(µ = 70.5) and the standard deviation of 1.16 inches.
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