Answer:
- 2 & 3
- 3 & 4
- 7 & 8
- 9 & 10
- 21 & 22
Step-by-step explanation:
#1
Since √(8) = √(2×4) = 2√2
then the √(8) lies between 2 & 3
#2
Since √(9) = 3 & √(16)= 4
then √(14) lies between 3 & 4
#3
√(60) = √(4×15) = 2√(15)
since √16 = 4 and 4 × 2 = 8
then 2√(15) < 8
∴ the √16 lies between 7 & 8
#4
√99 = √(9×11) = 3√11
√11 lies between √9 & √16 but closer to √9
& 3 × √16 = 12
the 3√11 = √99 likely lies between 9 & 10
#5
√444 = √(4×111)= 2√111
since √100 = 10 & √121 = 11
& 2×10= 20 & 2×11= 22
then 2√111 is likely between 21 & 22
