In the free-body diagram, the magnitude of the normal force is 35 N, the friction force is 15 N, and the net force is 70 N. What is the magnitude of the applied force? Explain how you came to your answer.

Answer:
15 N
Explanation:
Since the applied force only acts in the x-direction, the magnitude of the applied force is found by:
∑Fx=Fa-Ff=0 (assuming the block is not moving)
Therefore the equation becomes:
Fa=Ff
Fa=15 N in the positive x-direction