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newton's second law in 1 dimension: a catcher stops a 0.15-kg ball traveling at 40 m/s in a distance of 20 cm. what is the magnitude of the average force that the ball exerts against his glove?

Respuesta :

priyodiptobasak

Explanation:

v=0, u=40m/s, S=20cm =0.2m, mass = 0.15kg.

by the formula,

v²-u²=-2aS

0-1600=-20×0.2×a

-1600/(-2×0.2) = a

4000m/s²=a

Force = mass × acceleration.

F=ma = 0.15×4000 = 600N.

hope this helps you.

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