What is the answer to 2 and 3?

Answer:
p = -10
shortest side (a) = 5
longest side (b) = 12
Step-by-step explanation:
QUESTION 2: Solve for p by isolating the variable.
3/4 p - 1/4 p + 3 = -2 ----- subtract 3 from both sides
3/4 p - 1/4 p = -5
2/4 p = -5 ----- simplify 2/4
1/2 p = -5 ------ multiply 2 on both sides
p = -10
QUESTION 3:
Perimeter of a triangle = a + b + c
a = x
b = 3x - 3
c = 2x
x + 2x + 3x - 3 = 27 cm ------ combine like terms
6x - 3 = 27 ----- add 3 on both sides
6x = 30
x =5 ------- substitute 5 everywhere you see "x" for the side values
side a = x = 5
side b = 3x - 3 = 3(5) - 3 = 12
side c = 2x = 2(5) = 10
shortest side (a) = 5
longest side (b) = 12
Answer:
Answer to question 2:
[tex]\frac{\left(3\right)}{\left(4\right)}p-\frac{\left(1\right)}{\left(4\right)}p+3=-2\quad :\quad p= ?[/tex]
[tex]\frac{\left(3\right)}{\left(4\right)}p-\frac{\left(1\right)}{\left(4\right)}p+3=-2[/tex]
[tex]\frac{3}{4}p-\frac{1}{4}p+3=-2[/tex]
[tex]\mathrm{Subtract\:}3\mathrm{\:from\:both\:sides}[/tex]
[tex]\frac{3}{4}p-\frac{1}{4}p+3-3=-2-3[/tex]
[tex]\mathrm{Simplify}[/tex]
[tex]\frac{3}{4}p-\frac{1}{4}p=-5[/tex]
[tex]Simplify\\[/tex]
[tex]2p=-20[/tex]
[tex]\mathrm{Divide\:both\:sides\:by\:}2[/tex]
[tex]\frac{2p}{2}=\frac{-20}{2}[/tex]
[tex]p=-10[/tex]
_____________________________________
Answer to question 3
Measure of the shortest side is 5 cm
Measure of the longest side is 12 cm
Given:
Perimeter of ∆ = 27 cm
Side lengths of ∆: x, 2x, and 3x - 3
Required:
Measure of the shortest side and measure of the longest side.
Sum of all sides of the ∆ = Perimeter
Solve for x
Collect like terms
Add 3 to both sides
Divide both sides by 6
Length of each side of the ∆:
x = 5 cm
2x = 2(5) = 10 cm
3x - 3 = 3(5) - 3 = 15 - 3 = 12 cm
Measure of the shortest side is 5 cm
Measure of the longest side is 12 cm
Step-by-step explanation: