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A 0.038-kg bullet enters a 3.2-kg watermelon and embeds itself in the melon. The melon is immediately set into motion with a speed of 3.82 m/s. The bullet remains lodged inside the melon. What was the entry speed of the bullet (m/s)?

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leena

Hi there!

This is an example of a perfectly inelastic collection, so:

mb = mass of bullet

vb = velocity of bullet

mw = mass of watermelon

v = velocity final

mbvb = (mb + mw)v

Rearrange to solve for the velocity of the bullet:

vb = (mb + mw)v/mb

Plug in values:

vb = (0.038 + 3.2)(3.82)/(0.038) = 325.504 m/s

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