Triangle PQR has vertices P(-2,2), Q(8,2) and R(4,6).
(a) Find the equation of the perpendicular bisector of segment PQ.

I got so confused on this question if I could get help it would mean a lot

Respuesta :

9514 1404 393

Answer:

  x = 3

Step-by-step explanation:

You can forget about point R. It does not have any part in this problem, except to add confusion.

The given line PQ has the same y-coordinate values for points P and Q. This means the segment is a horizontal segment. Its perpendicular bisector will be a vertical line through its midpoint.

The midpoint (M) of PQ is ...

  M = (P +Q)/2

  M = ((-2, 2) +(8, 2))/2 = (-2+8, 2+2)/2 = (6, 4)/2

  M = (3, 2)

The vertical line through a point with x-coordinate 3 will have the equation ...

  x = 3

Ver imagen sqdancefan