Answer:
x^2-x+3
Step-by-step explanation:
(x^3-5x^2+7x-12)÷(x-4)
x^3−5x^2+7x−12
Factors of 12,
1,2,3,4,6,12
Substitute 4 into x. Since the result is 0, x-4 is a factor..
4^3−5×4^2+7×4−12=0
x-4
x^2 -x 3
x-4 | x^3 -5x^2 7x -12
x^3 -4x
-x^2 7x -12
-x^2 4x
3x -12
3x -12
x^2−x+3
(x^2−x+3)(x−4)
x−4
(x^2−x+3)
Answer = x^2-x+3
Hopes this helps
