Answer: 131.9 g
Explanation:
Write a Balanced Equation for the decomposition
CaCO₃ → CaO + CO₂
Find Moles of CO₂ Produced
Since the mole ratio of CaCO₃ to CO₂ is 1 to 1,
the moles of CaCO₃ = moles of CO₂
moles of CaCO₃ = mass ÷ molar mass
= 300 g ÷ 100.087 g/mol
= 2.997 moles
∴ moles of CO₂ = 2.997 moles
Determine Mass of CO₂
Mass = moles × molar mass
= 2.997 mol × 44.01 g/mol
= 131.9 g
∴ when 300 g of calcium carbonate is decomposed, it produces 131.9 g of carbon dioxide.
