The concentrations of all species in a 0.100 M Na₂CO₃ are:
1. The concentration of Na⁺ in the solution is 0.2 M.
2. The concentration of CO₃²¯ in the solution is 0.1 M
We'll begin by writing the dissociation equation for Na₂CO₃. This is illustrated below:
Na₂CO₃(aq) —> 2Na⁺(aq) + CO₃²¯(aq)
Thus, the species in Na₂CO₃ are Na⁺ and CO₃²¯
From the balanced equation above,
1 mole of Na₂CO₃ contains 2 moles Na⁺ and 1 mole of CO₃²¯
1. Determination of the concentration of Na⁺.
From the balanced equation above,
1 mole of Na₂CO₃ contains 2 moles Na⁺
Therefore,
0.100 M Na₂CO₃ will contains = 2 × 0.1 = 0.2 M Na⁺
Thus, the concentration of Na⁺ in the solution is 0.2 M.
2. Determination of the concentration of CO₃²¯
1 mole of Na₂CO₃ contains 1 mole of CO₃²¯
Therefore,
0.100 M Na₂CO₃ will also contains 0.100 M CO₃²¯
Thus, the concentration of CO₃²¯ in the solution is 0.1 M
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