Answer:
D. [tex]-\frac{\sqrt{2} }{2}[/tex]
Step-by-step explanation:
So, on a regular coordinate plane, coordinates are written (x,y)
well, in trig, coordinates are written (cosθ, sinθ).
if sinθ=[tex]\frac{\sqrt{2} }{2}[/tex] in the second quadrant, then look for the "y-value" that says
if you don't have a unit circle to look at, then it helps to know that the fraction [tex]\frac{\sqrt{2} }{2}[/tex] is ONLY found with ITSELF OR THE NEGATIVE OF ITSELF. it is never paired with another number.
this means that this number will only be seen in the coordinates
[tex](\frac{\sqrt{2} }{2} ,\frac{\sqrt{2} }{2})\\(-\frac{\sqrt{2} }{2},\frac{\sqrt{2} }{2})\\(-\frac{\sqrt{2} }{2},-\frac{\sqrt{2} }{2})\\(\frac{\sqrt{2} }{2},-\frac{\sqrt{2} }{2})[/tex]
use this knowledge along with knowing the signs in each quadrant:
Q1: (+,+)
Q2: (–,+)
Q3: (–,–)
Q4: (+,–)
