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A particular beer is 65.0% ethanol by volume . If a single bottle of beer contains a total of 750.0 mL of beer, what volume, in mL of ethanol (C₂H₆O), are present in the bottle?
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Respuesta :

samueladesida43

The volume in mL of ethanol (C₂H₆O) present in the bottle is 487.5L

HOW TO CALCULATE VOLUME OF ETHANOL:

  • According to this question, a particular beer is 65.0% ethanol by volume. This means that the beer contains 65/100 of ethanol.

  • If a single bottle of beer contains a total of 750.0 mL of beer, the volume of ethanol in the bottle is calculated as follows:

  • = 65/100 × 750

  • = 65 × 7.5

  • = 487.5mL

  • Therefore, volume in mL of ethanol (C₂H₆O) present in the bottle is 487.5L

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