Answer:
let the 1st number be x
then second number is x+2
then third number is x+2+2
according to question
sum of three consecutive odd integers is 237.
hence, x+x+2+x+2+2=237
3x+6=237
3x=237-6
3x=231
x=231/3
x=77
therefore 1st integer is 77
2nd integer is 77+2=79
3rd integer is 77+2+2=81
Answer:
77, 79, 81
Step-by-step explanation:
You can represent the equation as follows:
x + x + 2 + x + 4 =237
Combine like terms.
3x + 6 = 237
Subtract 6 from both sides.
3x = 231
Divide both sides by 3.
x = 77
Now, add 2 to 77 to determine the second integer.
77 + 2 = 79
Add 4 to 77 to determine the third integer.
77 + 4 = 81
