Use the following experiment. A state lottery game consists of choosing one card from each of the four suits in a standard deck of playing cards. (There are 13 cards in each suit.)

Count the number of ways in which four 8's can be chosen.

there are 4 way of choosing an ace card after choosing an ace card now we have 3 ways of choosing a king after choosing a king there are two ways of choosing a queen after choosing queen there is only one way of choosing a jack .

so the number of elements in the event is =4×3×2×1=24

we use permutation here for finding the total number of elements

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fichoh fichoh · Answer 2 · 2021-11-12T05:14:25+01:00

Using the concept of combination, since the order of selection doesn't matter, the number of ways in which four 8's can be chosen is 1

There are 13 cards in a suit :

Number of cards numbered 8 in a suit = 1

Number of ways of choosing a specific card :

(13C1) ÷ 13 = (13 ÷ 13) = 1 way

Since there are four different suits :

The number of ways of selecting a card numbered 8 from 3 each suit will be 1.

Hence, the number of ways in which four 8's can be chosen would be :

1 × 1 × 1 × 1 = 1

Therefore, there is only 1 way of choosing four 8's

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Use the following experiment. A state lottery game consists of choosing one card from each of the four suits in a standard deck of playing cards. (There are 13 cards in each suit.) Count the number of ways in which four 8's can be chosen.

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Use the following experiment. A state lottery game consists of choosing one card from each of the four suits in a standard deck of playing cards. (There are 13 cards in each suit.)

Count the number of ways in which four 8's can be chosen.