The null and hypothesis test; test statistic and the conclusion of the hypothesis are :
The hypothesis :
The test statistic :
[tex]\frac{\bar{x} - \mu}{\frac{σ}{\sqrt{n}}}[/tex]
Substituting the values into the equation :
[tex]\frac{2.5 - 3.0}{\frac{2}{\sqrt{50}}} = -1.7678[/tex]
The Pvalue, using a Pvalue calculator ; 1 - tailed ; 10% level of significance (0.10) = 0.038
Hence, Pvalue < 0.05
3.) At 10% level of significance ;
We compare the Pvalue and the α
α = 10% = 0.10
Since, Pvalue < α (0.038 < 0.10) ; then the result is significant.
Therefore, the result is significant at α = 0.10
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