When 2(y^2) + 8 is divided by 2y + 4 is equal to (y - 2) + (16 / (2y + 4)). The expression represents the quotient is the 2y + 4. While the expression represent the remainder is 16 / (2y + 4). The remainder of the given expression can also be solve using the remainder theorem.
Answer:
We need to perform division of 2y2 + 8 by 2y + 4. To solve this problem, we need to use the long method of division such as shown below:
y - 2 r. 16
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2y+4 √2y2 + 0y + 8
- (2y2 + 4y)
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0y2 - 4y + 8
- (-4y -8)
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0y + 16
The answer is y-2 + (16/(2y+4)) on which the remainder is 16 / (2y+4).
