a person on a bike (m=90 kg) is traveling 4 m/s at the top of a 2 m hill. what is the bikers total energy?

A) 1,944 J

B) 2,484 J

C) 1,764 J

D) 720 J

Respuesta :

towl35

Answer:

720 J

Explanation:

Kinetic Energy = 1/2 * m *(v*v)

M= 90 kg

V=4 m/s

KE=1/2 * 90 * (4*4)

KE= 45*16= 720 J

[tex]\frac{m}{s}[/tex]Answer: D) 720 J

Explanation:

Given : m=90kg

Total Energy = K. E. + P. E.  =[tex]\frac{1}{2}[/tex][tex]mv^{2}[/tex]+mgh

Since bike is present over a surface of Earth (top of hill) hence h=0m.

Therefore,

Total Energy=  [tex]\frac{1}{2}[/tex]*90kg*[tex](4m/s)^{2}[/tex]+(90kg)*(9.81[tex]\frac{m}{s}^2[/tex])x(0)

= 720 J

Hence total energy of bike is equal to 720 J