In a parking lot there are only white cars, green cars, and red cars. If one car is selected at random from the lot, the probability that the selected car would be a green car is one sixth and the probability that it would be a red car is one eighth. What is the probability that it would be a white car?

With the understanding that the three given cars form three mutually exhaustive and disjoint sets i.e., they form the partition of sample space, the probability that the selected car would be white is [tex]\frac{17}{24}[/tex].

What is partition of a sample space?

A collection of sets B1, B2, . . . , Bn is said to partition the sample space if the sets (i) are mutually disjoint and (ii) have as union the entire sample space.

In this question, we take three sets - set of all red cars, white cars and green cars.

A car can be either red, white or green. Thus they are mutually exclusive.

Also, let the cars in parking lot be the sample space. Every car we pick has to be of one of the three colors. This imply that the three sets of the three cars are mutually exhaustive.

P(selecting a red car) + P (selecting a green car) + P(selecting a white car) = 1

[tex]\frac{1}{8} + \frac{1}{6} + P(selecting\ a\ white\ car) = 1\\\\ P(selecting\ a\ white\ car) = \frac{17}{24}[/tex]

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