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In Example 2 we saw that Airbus A330-300s seat 330 passengers and cost $250 million each, Boeing 767-300ERs seat 270 passengers and cost $200 million each, while Boeing Dreamliner 787-9s seat 240 passengers and cost $250 million each. You are the purchasing manager of an airline company and have a spending goal of $4950 million for the purchase of new aircraft to seat a total of 5850 passengers. Your company has a policy of supporting U.S. industries, and you have been instructed to buy twice as many Boeings as Airbuses. Given the selection of three aircraft, how many of each should you order?

Respuesta :

MrRoyal

The number of order of each aircraft is an illustration of simultaneous equations.

You should order 7 Airbus A330-300s, 5 Boeing 767-300ERs and 9 Boeing Dreamliner 787-9s

To do this, we make use of the following representations:

  • A represents Airbus A330-300s
  • B represents Boeing 767-300ERs
  • C represents Boeing Dreamliner 787-9s

From the question, we have the following equations

[tex]\mathbf{330A + 270B + 240C = 5850}[/tex] ----the number of passengers

[tex]\mathbf{B + C = 2A}[/tex] --- the relationship between the number of planes

[tex]\mathbf{250A + 200B + 240C =4950 }[/tex] --- the budget

Make A the subject in [tex]\mathbf{B + C = 2A}[/tex]

[tex]\mathbf{A=\frac{1}{2}(B + C)}[/tex]

Substitute [tex]\mathbf{A=\frac{1}{2}(B + C)}[/tex] in [tex]\mathbf{330A + 270B + 240C = 5850}[/tex]

[tex]\mathbf{330 \times \frac{1}{2}(B + C) + 270B + 240C = 5850}[/tex]

[tex]\mathbf{165B + 165C + 270B + 240C = 5850}[/tex]

[tex]\mathbf{435B + 405C = 5850}[/tex]

Divide through by 15

[tex]\mathbf{29B + 27C = 390}[/tex]

Make C the subject

[tex]\mathbf{C = \frac{390 - 29B}{27}}[/tex]

Substitute [tex]\mathbf{A=\frac{1}{2}(B + C)}[/tex] in [tex]\mathbf{250A + 200B + 240C =4950 }[/tex]

[tex]\mathbf{250 \times \frac{1}{2}(B + C) + 200B + 240C =4950 }[/tex]

[tex]\mathbf{125B + 125C + 200B + 240C =4950 }[/tex]

[tex]\mathbf{325B + 365C =4950 }[/tex]

Divide through by 5

[tex]\mathbf{65B + 73C =990}[/tex]

Substitute [tex]\mathbf{C = \frac{390 - 29B}{27}}[/tex]

[tex]\mathbf{65B + 73\times\frac{390 - 29B}{27} =990}[/tex]

Multiply through by 27

[tex]\mathbf{65B \times 27+ 73\times(390 - 29B) =990 \times 27}[/tex]

[tex]\mathbf{1755B+ 28470 - 2117B =26730}[/tex]

Collect like terms

[tex]\mathbf{1755B- 2117B =26730 - 28470}[/tex]

[tex]\mathbf{-362B =-1740}[/tex]

Solve for B

[tex]\mathbf{B =\frac{1740}{362}}[/tex]

[tex]\mathbf{B =5}[/tex] --- approximated

Substitute [tex]\mathbf{B =5}[/tex] in [tex]\mathbf{C = \frac{390 - 29B}{27}}[/tex]

[tex]\mathbf{C = \frac{390 - 29 \times 5}{27}}}[/tex]

[tex]\mathbf{C = \frac{245}{27}}}[/tex]

[tex]\mathbf{C = 9}[/tex] --- approximated

Recall that: [tex]\mathbf{A=\frac{1}{2}(B + C)}[/tex]

So, we have:

[tex]\mathbf{A = \frac{1}{2} \times (5 + 9)}[/tex]

[tex]\mathbf{A = \frac{1}{2} \times 14}[/tex]

[tex]\mathbf{A = 7}[/tex]

Hence, you should order 7 Airbus A330-300s, 5 Boeing 767-300ERs and 9 Boeing Dreamliner 787-9s

Read more about simultaneous equations at:

https://brainly.com/question/16763389

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