Respuesta :
9514 1404 393
Answer:
I. 0.540; II. 0.694; III. 0.306; IV. 0.334; V. 0.177 ≠ 0.306 (not independent)
Step-by-step explanation:
I. P(ring) = 1100/2036 = 275/509 ≈ 0.540
The probability that a randomly selected bottle will have its ring attached is the ratio of such bottles to the total number of bottles: 1100/2036 ≈ 0.540.
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II. P(PET∨ring) = 1 -P(HDPE∧no ring) = 1 -623/2036 = 1413/2036 ≈ 0.694
The probability that a random bottle is PET or has the ring attached is the ratio of such bottles to the total: 1413/2036 ≈ 0.694.
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III. P(HDPE∧no ring) = 623/2036 ≈ 0.306
The probability that a random bottle is HDPE and has the ring removed is the ratio of such bottles to the total number of bottles: 623/2036 ≈ 0.306.
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IV. P(PET | no ring) = P(PET∧no ring)/P(no ring) = 313/936 ≈ 0.334
The probability that a random bottle is PET given that it has no ring is the ratio of ringless PET bottles to the total number of ringless bottles: 313/936 ≈ 0.334.
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V. P(ringless) = 936/2036 ≈ 0.460
P(HDPE) = 890/2036 ≈ 0.386
P(ringless)×P(HDPE) = 0.460×0.386 ≈ 0.177 ≠ P(HDPE∧no ring) = 0.306
If events A and B are independent, the probability of the joint event A∧B is the product of the probabilities of the individual events. Here the probability of an HDPE bottle having no ring is about 0.306, while the product of probabilities that a bottle is HDPE and that a bottle has no ring is about 0.177. "Ring removed" and "HDPE bottle type" are not independent.
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Attached is the recommended cross tabulation table. The numbers in blue are given in the problem statement (623 = 70%×890). The numbers in black are the numbers required in order to achieve the given totals.
