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10. Insert three numbers between 24 and 44 to give five numbers in an arithmetic progression. Consider: a = 24 and 44 as the last term. Calculate the difference (d) to insert the three numbers.​

Respuesta :

Abawiwaba

Answer:

29,34,39

Step-by-step explanation:

t1=24

tn=t1+(n-1)d

t5=24+(5-1)d

t5=44

44-24=20

(5-1)*d=20

d=5

t5=24+5(5-1)=44

so sub it for 2,3,4

t2=24+5(2-1)=29

t3=24+5(3-1)=34

t4=24+5(4-1)=39

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