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PLEASE HELP!!
(04.03)
Given the function g(x) = 5(2)^x, compare the average rate of change from x = 1 to x = 2 and from x = 3 to x = 4.
How many times greater is the average rate of change from x=3 to x=4 than from x=1 to x=2?
О 4 times
O 5 times
O 2 times
O The average rate of change of Section B is not greater than the average rate of change of Section A.

Respuesta :

Answer:  Choice A.   4 times

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Explanation:

We'll be using this formula

[tex]m = \frac{f(b)-f(a)}{b-a}[/tex]

to compute the average rate of change (AROC) from x = a to x = b. Note how this is effectively the slope formula because y = f(x).

To start things off, we'll compute the AROC from x = 1 to x = 2.

[tex]m = \frac{g(b)-g(a)}{b-a}\\\\m = \frac{g(2)-g(1)}{2-1}\\\\m = \frac{5(2)^2-5(2)^1}{2-1}\\\\m = \frac{10}{1}\\\\m = 10\\\\[/tex]

Do the same for the AROC from x = 3 to x = 4.

[tex]m = \frac{g(b)-g(a)}{b-a}\\\\m = \frac{g(4)-g(3)}{4-3}\\\\m = \frac{5(2)^4-5(2)^3}{4-3}\\\\m = \frac{40}{1}\\\\m = 40\\\\[/tex]

The jump from m = 10 to m = 40 is "times 4", which is why choice A is the final answer.