The clock cycle time in a pipelined and non-pipelined processor will be 350ps and 1250ps respectively.
1. The clock cycle time in a pipelined processor will be the slowest instruction decode which is 350ps. The clock cycle time in a non-pipelined processor will be:
= 250 + 350 + 150 + 300 + 200
= 1250ps
2. The total latency of an LW instruction in a pipelined processor will be:
= 5 × 350 = 1750ps.
The total latency of an LW instruction in a non-pipelined processor will be:
= 250 + 350 + 150 + 300 + 200
= 1250ps
3. Based on the information asked, the stage to be split will be the cycle time. Now, the new cycle time will be based on the longest stage which will be 300ps.
4. It should be noted that the store and load instruction is used for the utilization of memory. The load instruction is 20% of the time while the store instruction is 15% of the time. Therefore, the utilization of data memory will be:
= 20% + 15% = 35%
5. The utilization of the write-register port of the "Registers" unit will be:
= 20% + 45% = 65%
6. The multi cycle execution time will be:
= (5 × 20%) + [4 × (45% + 20% + 15%)]
= (5 × 0.2) + (4 × 0.8)
= 1 + 3.2
= 4.2
The single cycle execution time will be:
= Cycle time non-pipeline / Cycle time pipeline
= 1250/350
= 3.5
Read related link on:
https://brainly.com/question/25231696