The initial horizontal velocity of the projectile is 22.1 m/s.
The given parameters;
- height of the projectile, h = 25 m
- horizontal distance of the object, R = 50 m
The time of motion of the object is calculated as follows;
h = ut + ¹/₂gt²
where;
- u is the initial vertical velocity = 0
h = ¹/₂gt²
[tex]t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\times 25}{9.8} } \\\\t = 2.26 \ s[/tex]
The initial horizontal velocity of the projectile is calculated as follows;
R = vₓt
[tex]v_x = \frac{R}{t} \\\\v_x = \frac{50}{2.26} \\\\v_x = 22.1 \ m/s[/tex]
Thus, the initial horizontal velocity of the projectile is 22.1 m/s.
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