Answer:
Below
Explanation:
For these types of questions, you should draw out your triangles and resultant vectors.
For this, we can use the pythagorean theorem to solve this :
vpf^2 = vpi^2 + vw^2
vpf^2 = 45^2 + 191^2
vpf = [tex]\sqrt{38507[/tex]
vpf = 196.2294
vpf = 200 mph
Now we need to find the angle of the plane's direction using soh cah toa
Tan(x) = O / A
x = tan^-1(191/45)
x = 76.74
x = 77 degrees
Therefore, the plane's result velocity is 200 mph [ E 77 N ]
Hope this helps!
