Answer:
Assuming that the multiplicities of the five aforementioned roots ( {0, 5, 1, 3i, -3i} ) are each 1, the 6th zero can be any real number.
Step-by-step explanation:
Because P(X) has real coefficients, and 3i is a zero, we conclude that -3i is also a zero of P(X). Assuming that the multiplicities of the five aforementioned roots ( {0, 5, 1, 3i, -3i} ) are each 1, the 6th zero can be any real number.
