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In AHIJ, the measure of ZJ=90°, the measure of ZI=62°, and IJ = 57 feet. Find the
length of JH to the nearest tenth of a foot.

In AHIJ the measure of ZJ90 the measure of ZI62 and IJ 57 feet Find the length of JH to the nearest tenth of a foot class=

Respuesta :

bhagyasanduni028

Answer:

[tex]x = 107.2[/tex]

Step-by-step explanation:

[tex]57 = ih \cos(62) \\ ih = \frac{57}{ \cos(62) } \\ \\ x = ih \sin(62) \\ x = \frac{57}{ \cos(62) } \times \sin(62) \\ x = 107.2[/tex]

xiaoline4ever

Answer:

Step-by-step explanation:

The graph had prove the adjacent length of angle ZI, which is 57. And asks the opposite side of angle ZI, we use tan. to solve for x.

tan (62) = opposite side / adjacent side

tan (62) = x / 57

tan (62) x 57 = x

x = 107.2

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