Answer: [tex]\frac{tv^3}{u^8}\\\\\\[/tex]
This is the fraction tv^3 all over u^8
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Work Shown:
[tex]\frac{t^2uv^7}{tu^9v^4}\\\\\\\frac{t^2}{t}*\frac{u}{u^9}*\frac{v^7}{v^4}\\\\\\t^{2-1}*u^{1-9}*v^{7-4}\\\\\\t^{1}*u^{-8}*v^{3}\\\\\\\frac{t}{1}*\frac{1}{u^8}*\frac{v^3}{1}\\\\\\\frac{t*1*v^3}{1*u^8*1}\\\\\\\frac{tv^3}{u^8}\\\\\\[/tex]
In the third step, I used the rule (a^b)/(a^c) = a^(b-c)
To make the negative exponent turn positive, we apply the reciprocal to the base.
