Given info:- [tex]\textsf{If (√3+√2)/(3√2-2√3) = x+y√6,} [/tex]
[tex]\textsf{then find the value of x and y?}[/tex]
Explanation:-
[tex]\textsf{Consider LHS=}\\[/tex]
[tex] \rm \: \frac{ \sqrt{2 } + \sqrt{3} }{3 \sqrt{2} - 2 \sqrt{3} } \\ [/tex]
[tex] \rm \: = \frac{ \sqrt{2 } + \sqrt{3} }{3 \sqrt{2} - 2 \sqrt{3} } \times \frac{3 \sqrt{2} + 2 \sqrt{3} }{3 \sqrt{2} + 2 \sqrt{3} } \\ [/tex]
[tex] = \rm \: \frac{( \sqrt{2 } + \sqrt{3} )(3 \sqrt{2} + 2 \sqrt{3} )}{(3 \sqrt{2} - 2 \sqrt{3})(3 \sqrt{2} + 2 \sqrt{3}) } \\ [/tex]
[tex] \rm \: = \frac{3 \sqrt{2 \times 2} + 2 \sqrt{3 \times 2} + 3 \sqrt{2 \times 3} + 2 \sqrt{3 \times 3} }{(3 \sqrt{2} {)}^{2} - (2 \sqrt{3} {)}^{2} } \\ [/tex]
[tex] \rm = \frac{3 \times 2 + 2 \sqrt{6} + 3 \sqrt{6} + 2 \times 3}{18 - 12} \\ [/tex]
[tex] \rm \: = \frac{12 + 5 \sqrt{6} }{6} \\ [/tex]
[tex] \rm \: = 2 + \frac{5}{6} \sqrt{6} \\ [/tex]
[tex] \rm \therefore \: 2 + \frac{5}{6} \sqrt{6} = x + y \sqrt{6} \\ [/tex]
[tex]\textsf{On, comparing with RHS we notice that:}\\[/tex]
[tex]\textsf{the value of x = 2 and y = 5/6.}\\[/tex]
[tex]\bf{Read more:}[/tex]
[tex]\textsf{Similar questions}\\[/tex]
[tex] \sqrt{6} + \sqrt{11} \div \sqrt{5} + \sqrt{3} [/tex] A. [tex] \sqrt{30} + 3 \sqrt{2} + \sqrt{55} + \sqrt{33} \div 8[/tex] B. [tex] \sqrt{30} - 3 \sqrt{2} ...
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