Respuesta :
Considering that each of 2, 4, and 6 is twice as likely to come up as each of 1, 3, and 5, the probability distribution is given by:
[tex]P(X = 1) = 0.1111[/tex]
[tex]P(X = 2) = 0.2222[/tex]
[tex]P(X = 3) = 0.1111[/tex]
[tex]P(X = 4) = 0.2222[/tex]
[tex]P(X = 5) = 0.1111[/tex]
[tex]P(X = 6) = 0.2222[/tex]
The symbolic distribution is:
[tex]P(X = 1) = y[/tex]
[tex]P(X = 2) = x[/tex]
[tex]P(X = 3) = y[/tex]
[tex]P(X = 4) = x[/tex]
[tex]P(X = 5) = y[/tex]
[tex]P(X = 6) = x[/tex]
The sum of all probabilities is 1, hence:
[tex]3x + 3y = 1[/tex]
Simplifying by 3:
[tex]x + y = 0.3333[/tex]
[tex]y = 0.3333 - x[/tex]
2, 4, and 6 is twice as likely to come up as each of 1, 3, and 5, hence:
[tex]x = 2y[/tex]
[tex]x = 2(0.3333 - x)[/tex]
[tex]3x = 0.6667[/tex]
[tex]x = \frac{0.6667}{3}[/tex]
[tex]x = 0.2222[/tex]
Then:
[tex]y = 0.3333 - x = 0.3333 - 0.2222 = 0.1111[/tex]
Hence, the distribution is:
[tex]P(X = 1) = 0.1111[/tex]
[tex]P(X = 2) = 0.2222[/tex]
[tex]P(X = 3) = 0.1111[/tex]
[tex]P(X = 4) = 0.2222[/tex]
[tex]P(X = 5) = 0.1111[/tex]
[tex]P(X = 6) = 0.2222[/tex]
A similar problem is given at https://brainly.com/question/24855677
