The probability that the bill will be less than $100 is 7%
The z score is used to determine by how many standard deviations the raw score is above or below the mean. It is given by:
[tex]z=\frac{x-\mu}{\sigma} \\\\x=raw\ score, \sigma=standard\ deviation, \mu=mean\\\\\\Given\ that\ \sigma=32,\mu=147,hence:\\\\For\ x<100:\\\\z=\frac{100-147}{32}=-1.47[/tex]
From the normal distribution table, P(x < 100) = P(z < -1.47) = 0.0708 = 7.08%
The probability that the bill will be less than $100 is 7%
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