A rectangle is drawn so the width is 7 inches longer than the height. If the rectangles diagonal measurement is 44 inches, find the height

Respuesta :

Abu99

Answer:

h = 27.4 in

Step-by-step explanation:

Height = h

Width = h + 7

Diagonal = 44

These 3 form a right-angle triangle, we can therefore use pythagoras theorem to formulate a solveable equation to find h:

h² + (h + 7)² = (44)²

h² + h² + 14h + 49 = 1936

2h² + 14h - 1887 = 0

[tex]2(h^{2} + 7h -\frac{1887}{2}) = 0 \\\\ 2((h + \frac{7}{2})^{2}-\frac{49}{4} -\frac{1887}{2}) = 0 \\\\ 2((h + \frac{7}{2})^{2}-\frac{3823}{4}) = 0 \\\\ 2(h + \frac{7}{2})^{2} - \frac{3823}{2} = 0 \\\\ (h + \frac{7}{2})^{2} = \frac{3823}{4} \\\\ h + \frac{7}{2} = \frac{+}{}\frac{\sqrt{3823}}{2} \\\\ h = -\frac{7}{2} \frac{+}{} \frac{\sqrt{3823}}{2} \\\\ h = 27.4152... \ or \ h = -34.4152...[/tex]

The height cannot be a negative value ∴ the height we are looking for is the other.

h = 27.4 in