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There are only red sweets and yellow sweets in a bag.
There are n red sweets in the bag.
There are 8 yellow sweets in the bag.
Sajid is going to take at random a sweet from the bag and eat it.
7
He says that the probability that the sweet will be red is
10
7
10
(a) Show why the probability cannot be

There are only red sweets and yellow sweets in a bag There are n red sweets in the bag There are 8 yellow sweets in the bag Sajid is going to take at random a s class=

Respuesta :

Using the probability concept, it is found that since the number of red sweets would be a decimal number, the probability cannot be [tex]\frac{7}{10}[/tex]

A probability is the number of desired outcomes divided by the number of total outcomes.

In this problem:

  • In total, there are 8 + n sweets in the bag.
  • Of those, n are red.

The probability of red is:

[tex]p = \frac{n}{n + 8}[/tex]

Supposing [tex]p = \frac{7}{10}[/tex], we solve for n:

[tex]\frac{n}{n + 8} = \frac{7}{10}[/tex]

[tex]10n = 7n + 56[/tex]

[tex]3n = 56[/tex]

[tex]n = \frac{56}{3}[/tex]

[tex]n = 18.67[/tex]

Since the number of red sweets would be a decimal number, the probability cannot be [tex]\frac{7}{10}[/tex]

A similar problem is given at https://brainly.com/question/15536019

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