Answer:
Step-by-step explanation:
I will ASSUME that the force vector F = 2i + 8j
which has a magnitude of
F = √(2² + 8²) = √68
which has a direction of
θ = arctan (8/2) = 75.96°
The movement has a distance of
d = √((13 - 2)² + (10 - 5)²) = √146 ft
and a direction of
φ = arctan((10 - 5)/(13 - 2)) = 24.44³
the angle between force and motion is
75.96 - 24.44 = 51.52°
Work is the force in the direction of motion times the distance moved.
W = Fd = (√68)(cos51.52)(√146) = 62 J
or we could just break it into components
x direction work = Fd = 2(13 - 2) = 22 J
y direction work = Fd = 8(10 - 5) = 40 J
total work W = 22 + 40 = 62 J
