Respuesta :

The angle of elevation of the shell must be approximately 25.840° in order to have a reach of 20 kilometers.

The shell experiments a parabolic motion, which is a combination of horizontal uniform motion and vertical uniform accelerated motion. If initial height of the shell is the same that its final height, then the range of the shell ([tex]d[/tex]), in meters, is described by the following expression:

[tex]d = \frac{v^{2}}{g}\cdot \sin 2\theta[/tex] (1)

Where:

  • [tex]v[/tex] - Initial speed of the shell, in meters per second
  • [tex]g[/tex] - Gravitational acceleration, in meters per square second
  • [tex]\theta[/tex] - Angle of elevation, in sexagesimal degrees

If we know that [tex]v = 500\,\frac{m}{s}[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex] and [tex]d = 20000\,m[/tex], then the angle of elevation is:

[tex]\sin 2\theta = \frac{d\cdot g}{v^{2}}[/tex]

[tex]\theta = \frac{1}{2}\cdot \sin^{-1} \frac{d\cdot g}{v^{2}}[/tex]

[tex]\theta = \frac{1}{2}\cdot \sin^{-1} \frac{(20000\,m)\cdot \left(9.807\,\frac{m}{s^{2}} \right)}{\left(500\,\frac{m}{s} \right)^{2}}[/tex]

[tex]\theta \approx 25.840^{\circ}[/tex]

The angle of elevation of the shell must be approximately 25.840° in order to have a reach of 20 kilometers.

To learn more on parabolic motion, we kindly invite to check this question: https://brainly.com/question/1259873