Respuesta :
The probability of an event occurring is given by the ratio of the number of
possible outcome to the number of required outcome.
- First question: The probability that the first coin lands on heads and the second coin lands on tails is 0.25.
- Second question: The probability of drawing a black card and then a 8 is [tex]\underline{\dfrac{1}{13}}[/tex].
- Third question: The probability that the number chosen is 4 and the letter chosen is a consonant, is [tex]\underline{\dfrac{21}{234}}[/tex].
- Fourth question: The probability that the first die lands on an even number and the second die is less than 2, is [tex]\underline{\dfrac{1}{12}}[/tex].
Reasons:
First question:
The number of faces in a coin = 2; A head or a tail
The probability that the first coin lands on heads, P(H) = [tex]\dfrac{1}{2}[/tex]
The probability that the second coin lands on tails, P(T) = [tex]\dfrac{1}{2}[/tex]
The probability that the first coin lands on heads and the second coin lands
on tails = P(H ∩ T)
Which gives;
[tex]P(H \cap T) = \dfrac{1}{2} \times \dfrac{1}{2} = \dfrac{1}{4}[/tex]
The probability that the first coin lands on heads and the second coin lands on tails = [tex]\dfrac{1}{4}[/tex] = 0.25
Second question:
The number of black cards in a pack of 52 = 26 cards
The number of cards that are a 8 in a pack of 52 cards = 8 cards
[tex]\mathrm{The \ probability \ of \ drawing \ a \ black \ card}, \ P(B) = \dfrac{26}{52} = \dfrac{1}{2}[/tex]
[tex]\mathrm{The \ probability \ of \ drawing \ a \ 8,} \ P(8) = \dfrac{8}{52} = \dfrac{2}{13}[/tex]
The probability of drawing a black card and then an 8, P(B∩8), is given as follows;
[tex]P(B \cap 8) = \dfrac{1}{2} \times \dfrac{2}{13} = \dfrac{1}{13}[/tex]
The probability of drawing a black card and then a 8 is P(B∩8) = [tex]\underline{\dfrac{1}{13}}[/tex]
Third question:
The probability that a number chosen between 0 and 9 is 4, P(4) = [tex]\dfrac{1}{9}[/tex]
The number of consonant in the alphabet = 21
The probability that a letter chosen from A to Z is a consonant, P(C) = [tex]\dfrac{21}{26}[/tex]
The probability that the number chosen is 4 and the letter chosen is a consonant, P(4 ∩ C) = [tex]\dfrac{1}{9} \times \dfrac{21}{26} = \underline{ \dfrac{21}{234}}[/tex]
Fourth question:
The number of even numbers on a die = 3; (2, 4, 6)
The number of numbers less than 2 on a die = 1
The probability that the first die lands on an even number, P(E) = [tex]\dfrac{3}{6}[/tex]
The probability that the second die is less than 2. P(<2) = [tex]\dfrac{1}{6}[/tex]
Therefore;
The probability that the first die lands on an even number and the second die is less than 2, P(E ∩ <2) = [tex]\dfrac{3}{6} \times \dfrac{1}{6} = \dfrac{3}{36} = \underline{\dfrac{1}{12}}[/tex]
Learn more here:
https://brainly.com/question/19916581
