Three integers sum to 57. The second integer is twice the first integer. The third integer is seven less than five times the first integer. What are the three integers?

Respuesta :

Answer:

a=8

b=16

c=33

Step-by-step explanation:

Let's call the integers a, b, and c. (a is the first, b is the second, and c is the third.)

a+b+c=57

Write the second two sentences as equations.

b=2a

c=5a-7

Plug in these values of b and c to the original equation.

a+(2a)+(5a-7)=57

Solve for a:

a+2a+5a-7=57

8a-7=57

8a=64

a=8

Now, plug in your solution for a into the equations for b and c to solve for them.

b=2a=2(8)=16

c=5a-7=5(8)-7=40-7=33

You can add up your answers for a, b, and c to make sure you're correct.

a+b+c=8+16+33=57

I hope this helped!