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[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]

[tex] \boxed{ \boxed{3 \leqslant n < 7}}[/tex]

The equivalent expression is ~

[tex] \large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}[/tex]

Let's solve ~

  • [tex]12 \leqslant 4n < 28[/tex]

Now divide each term with 4

  • [tex]12 \div 4 \leqslant 4n \div 4 < 28 \div 4[/tex]

  • [tex]3 \leqslant n < 7[/tex]

Sᴘᴀᴄᴇ7

[tex] \sf \: 12 ≤ 4n < 28[/tex]

  • Divide all parts by 4

[tex]\sf \longmapsto \frac{12}{4}≤ \frac{4n}{4} < \frac{28}{4} [/tex]

[tex] \sf \longmapsto3≤n<7[/tex]

Result:

[tex]\boxed{ \sf 3 \leqslant n<7}[/tex]

  • Number line attached
Ver imagen Sᴘᴀᴄᴇ7

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