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A student conducts an experiment to separate water into hydrogen and oxygen through a chemical reaction as shown below.

H Hydrogen gas Orygengu rises in this test tube test tube.

2 H2O --> 2H2 + O2

As a result the student collects 28.0 g of hydrogen and 224.0 g of oxygen. How many grams of water did the student originally start with?
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A student conducts an experiment to separate water into hydrogen and oxygen through a chemical reaction as shown below H Hydrogen gas Orygengu rises in this tes class=

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The amount, in grams, of water, that the student originally started with would be 252 g

From the balanced equation of the reaction, the ratio of H2O to H2 is 1:1. Thus for every 1 mole of water that is separated, 1 mole of H2 is produced.

Recall that: mole = mass/molar mass

Mole of 28.0 g H2 produced = 28/2

                                              = 14 moles

Equivalent mole of H2O would, therefore, be 14 moles.

Mass of 14 moles H2O = mole x molar mass

                                      = 14 x 18

                                      = 252 g

More on stoichiometric calculation can be found here:  https://brainly.com/question/8062886?referrer=searchResults

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