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An object is dropped from a height of 288 feet. The equation, - 16t ^ 2 + 288t = h(t) represents the height, hof the object after tseconds. How long does it take the object to the ground?

0 seconds
16 seconds
18 seconds
88 seconds

Respuesta :

Trancescient

18 seconds

Step-by-step explanation:

The object will reach the ground when its height h(t) = 0. Therefore, we can write

[tex]h(t) = 288t - 16t^2 = 0 \Rightarrow 16t^2 = 288t[/tex]

Solving for t, we get

[tex]16t = 288 \Rightarrow t = 18\:\text{s}[/tex]

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