Respuesta :
The given information can be written as an equation from which the
solution can be found.
- [tex]Question \ 1: \displaystyle \underline{\frac{14 - 6}{6 - 2} \ <\ 4 \times (10 - 8)- 2 \times 2}[/tex]
- Question 2: The equation is 0.4 × n = 8; n = 20
- Question 3: The equation is C + $3.49 = $9.84; The solution is the original cost, C = $6.35
Reasons:
Question 1: The possible expression is presented as follows;
[tex]\displaystyle \frac{14 - 6}{6 - 2} \ and \ 4 \times (10 - 8)- 2 \times 2[/tex]
The comparison values are;
<, >, or =
Solution:
[tex]\displaystyle \frac{14 - 6}{6 - 2} = \frac{8}{4} = 2[/tex]
4 × (10 - 8) - 2 × 2 = 4
2 < 4
Therefore;
[tex]\displaystyle \underline{\frac{14 - 6}{6 - 2} \ <\ 4 \times (10 - 8)- 2 \times 2}[/tex]
Question 2: The given statement can be presented as the following equation:
0.4 × n = 8
The solution of the above equation is therefore;
[tex]\displaystyle n = \frac{8}{0.4} = 20[/tex]
n = 20
Question 3: The amount by which the cost of the toy is increased = $3.49
New price of the toy = $9.84
The original cost of the toy = C
The equation is therefore, C + 3.49 = 9.84
C = 9.84 - 3.49 = 6.35
The original cost of the toy, C = $6.35
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