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To determine the heat of neutralisation, Chelsea placed 50 cm' of sodium hydroxide
solution of concentration 1.0 mol dm- in a polystyrene cup and recorded its
temperature. She then recorded the temperature of 50 cm of sulfuric acid, added it
to the cup, stirred the solution and recorded its maximum temperature, as follows:
. initial temperature of NaOH(aq) = 29.5 °C
. initial temperature of H.SO, (aq) = 29.9 °C
• maximum temperature of the solution = 35.8 °C

Calculate the increase in temperature

Respuesta :

dsdrajlin

2 solutions of NaOH and H₂SO₄ at 29.5 °C are mixed in a coffee-cup calorimeter and after the reaction is completed the temperature is 35.8 °C. The increase in the temperature is 6.3 °C.

To determine the heat of neutralization, Chelsea used a coffee-cup calorimeter.

Initially, she had 2 solutions, NaOH and H₂SO₄, both at 29.5 °C. Upon mixing, the heat was evolved and the final temperature of the solution was 35.8 °C. The neutralization reaction was:

NaOH + H₂SO₄ ⇒ Na₂SO₄ + H₂O

The increase in temperature (ΔT) is equal to the difference between the final temperature and the initial temperature.

[tex]\Delta T = 35.8 \° C - 29.5 \° C = 6.3 \° C[/tex]

This data can be used to calculate the heat of neutralization (q) using the following expression.

[tex]q = c \times m \times \Delta T[/tex]

where,

  • c is the specific heat capacity of the solution
  • m is the mass of the solution

2 solutions of NaOH and H₂SO₄ at 29.5 °C are mixed in a coffee-cup calorimeter and after the reaction is completed the temperature is 35.8 °C. The increase in the temperature is 6.3 °C.

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