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The temperature of a substance in an experiment changes by −8.7°F from 10 a.m. to 1 p.m. At 5 p.m., the temperature is 33.5°F. It is 23 of what the temperature was at 1 p.m.

What was the temperature at 10 a.m. of the substance?

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Respuesta :

Using proportions, it is found that the temperature at 10 a.m. of the substance was of 58.95ºF.

  • At 5 p.m, the temperature is 33.5°F, which is [tex]\frac{2}{3}[/tex] of the temperature x at 1 p.m, hence:

[tex]\frac{2}{3}x = 33.5[/tex]

Applying cross multiplication:

[tex]2x = 3(33.5)[/tex]

Simplifying both sides by 2:

[tex]x = 1.5(33.5)[/tex]

[tex]x = 50.25[/tex]

At 10 a.m, the temperature was 8.7°F higher, hence:

[tex]y = 50.25 + 8.7 = 58.95[/tex]

The temperature at 10 a.m. of the substance was of 58.95ºF.

A similar problem is given at https://brainly.com/question/24372153

yuly3000

Answer:

F = 58.95

Step-by-step explanation: I took the test

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