The tension in the cable at the given weight of worker is 15,255.3 N.
The given parameters;
- mass of the construction, = 80 kg
- position of the worker, = 2 m
- mass of the steel, = 1450 kg
- length of the steel beam = 6 m
A sketch of the force diagram is presented as follows;
|-------- 3 m --------|--- 1 m ---|---- 2 m ---|
↑ Tsin(30)
A---------------------------------------------------- ← Tcos(30)
↓ ↓
1450 kg 80 kg
Take moment about point A:
[tex]1450 \times 9.8 \ \times 3 \ + \ 80 \times 9.8\times 4 - Tsin(30)\times 6 = 0\\\\45766-3 T = 0\\\\T = \frac{45766}{3} \\\\T = 15,255.3 \ N[/tex]
Thus, the tension in the cable at the given weight of worker is 15,255.3 N.
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